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22 August, 21:44

What is the oxidation number of each phosphorus atom in H4P2O7

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  1. 22 August, 22:41
    0
    +5

    Explanation:

    The oxidation number of phosphorus can be obtained as follows:

    H4P2O7 = 0

    4 (+1) + 2P + 7 (-2) = 0

    4 + 2P - 14 = 0

    Collect like terms

    2P = 14 - 4

    2P = 10

    Divide both side by 2

    P = 10/2

    P = + 5

    The oxidation number of phosphorus is + 5
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