a gaseous mixture of O2 and N2 has 22.8% of the pressure exerted by N2. What is the partial pressure of oxygen in the mixture, if the total pressure is 785.0 mmHg?

The partial pressure of oyxgen O2 is 606 mmHg

Explanation:

Step 1: Data given

Percentage N2 = 22.8 %

The total pressure = 785.0 mmHg

Step 2: Calculate partial pressures

Partial pressure = percentage * total pressure

Partial pressure N2 = 0.228 * 785.0 mmHg

Partial pressure N2 = 179 mmHg

Step 3: Calculate partial pressure O2

Partial pressure O2 = 785.0 mmHg - 179.0 mmHg

Partial pressure O2 = 606 mmHg

OR (1 - 0.228) * 785.0 = 606 mmHg

The partial pressure of oyxgen O2 is 606 mmHg