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15 August, 15:13

How much energy must be transferred as heat to the 420 kg of water in a bathtub in order to raise the water temperature from 25 degrees celsius to 37 degrees celsius

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  1. 15 August, 16:34
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    Answer: 21,072.24KJ

    Explanation:

    increasing the temperature of 420 kg of water from 25 degrees C to 37degrees C. The change in temperature is ∆T = (37 - 25) degrees C = 12 degrees C.

    The specific heat capacity of water is 4,181 J / kg degree C, so the equation gives:

    Q=mC ∆T

    Q = 420 kg * 4181 J / kg degree C * 12 degrees C

    =21, 072,240 J = 21,072.24 kJ
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