A sample of neon gas has a pressure of 2.50 atm in a 2.50 L container, at what volume will

neon have a pressure of 9.68?

0.65L

Explanation:

Data obtained from the question include:

P1 = 2.50atm

V1 = 2.50L

P2 = 9.68atm

V2 = ?

The new volume can be obtain as follows:

P1V1 = P2V2

2.5 x 2.5 = 9.68 x V2

Divide both side by 9.68

V2 = (2.5 x 2.5) / 9.68

V2 = 0.65L