An 80.0g sample of an unknown metal is at an initial temperature of 55.5oC. Afer 540 J of energy is absorbed by the metal, the temperature of the metal increasese to 81.75oC. What is the specific heat of the unknown metal (assume no phase change occurs) ? Include units in your answer. Show work if possible.

Specific heat of metal = 0.26 j/g.°C

Explanation:

Given dа ta:

Mass of sample = 80.0 g

Initial temperature = 55.5 °C

Final temperature = 81.75 °C

Amount of heat absorbed = 540 j

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 81.75 °C - 55.5 °C

ΔT = 26.25 °C

540 j = 80 g * c * 26.25 °C

540 j = 2100 g.°C * c

540 j / 2100 g.°C = c

c = 0.26 j/g.°C