A balloon originally has 0.10 moles of helium and has a volume of 0.50 L. If 0.59 grams of He are added to the balloon, what will the new volume be?

V = 0.7375L

Explanation:

Number of moles n1 = 0.10moles

Volume V1 = 0.5L

Mass = 0.59g

Molar mass = 4.0g / mol

N2 = mass / molar mass

n2 = 0.59 / 4.0 = 0.1475 moles

The volume (V) of an ideal gas varies directly with the number of moles of the gas (n) when the pressure (P) and the number of temperature (T) are constant.

We can express this mathematically as:

V∝natconstantPandT

V=constant * (n) orVn=constant

V1 / n1 = V2 / n2

V1 * n2 = V2 * n1

Solve for V2

V2 = (V1 * n2) / n1

V2 = (0.5 * 0.1475) / 0.10

V2 = 0.7375L