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3 March, 17:12

5. Identifying the limiting reagent: Given the reaction 2Cu + S → Cu2S, if you had 3 moles of both Cu and S, which would you run out of first?

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  1. 3 March, 20:45
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    The reaction is

    2Cu + S → Cu2S

    So as per balanced given reaction we need one mole of sulphur over two moles of copper

    Or

    To react with one mole of sulphur we need two moles of copper

    Thus we can say that the mole ration required for complete reaction will be

    Cu : S = 2 : 1

    As per the given problem the moles of each Cu and S are 3 moles

    Thus for each three moles of given sulphur we need six moles of Cu to give three moles of Cu2S

    However we have only three moles of copper available

    So the limiting reagent is copper

    It is going to decide the actual yield of reaction

    The three moles of Copper will get completely utilized and only 1.5 moles of S will be used in the reaction making S an excess reagent

    The moles of S left will be = 1.5 moles

    moles of Cu2S formed = 1.5 moles
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