Ask Question
3 May, 13:36

The equilibrium constant, Kc, for the following reaction is 9.52E-2 at 350 K. CH4 (g) CCl4 (g) 2 CH2Cl2 (g) Assuming that you start with equal concentrations of CH4 and CCl4 and no CH2Cl2 is initially present, describe the relative abundance of each species present at equilibrium. 1 [CCl4] 1 [CH4] 2 [CH2Cl2] 1) Lower 2) Higher 3) Can't tell

+4
Answers (1)
  1. 3 May, 17:33
    0
    [CCl₄] = Lower.

    [CH₄] = Lower.

    [CH₂Cl₂] = Higher.

    Explanation:

    Based in the reaction:

    CH₄ (g) + CCl₄ (g) → 2CH₂Cl₂ (g)

    Kc is defined as:

    Kc = 9.42x10⁻² = [CH₂Cl₂]² / [CCl₄] [CH₄]

    Where the concentrations of the compounds are concentrations in equilibrium.

    If you start with just CH₄ and CCl₄ the reaction will produce CH₂Cl₂ until the ratio of [CH₂Cl₂]² / [CCl₄] [CH₄] = Kc

    That means CH₄ and CCl₄ will decrease in concentration and CH₂Cl₂ will increase its concentrations. Thus, in equilibrium the relative abundance of species are:

    [CCl₄] = Lower.

    [CH₄] = Lower.

    [CH₂Cl₂] = Higher.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The equilibrium constant, Kc, for the following reaction is 9.52E-2 at 350 K. CH4 (g) CCl4 (g) 2 CH2Cl2 (g) Assuming that you start with ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers