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10 June, 00:47

A student has two solutions of a substance; Solution-1:25M, 400ml and Solution-2:30M, 300M. What is the molarity of the final solutions if these two solutions are mixed?

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  1. 10 June, 02:05
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    The molarity of the final solution is 1.7 M

    Explanation:

    The parameters given are;

    First solution = 400 ml of 1.25 M

    Second solution = 300 ml of 2.30 M

    Therefore, we have;

    First solution contains 400/1000 * 1.25 moles = 0.5 moles of the substance

    Second solution contains 300/1000 * 2.30 moles = 0.69 moles of the

    Hence the sum of the two solutions contains 0.5 + 0.69 = 1.19 moles of the substance

    The volume of the sum of the two solutions = 400 ml + 300 ml = 700 ml

    Hence we have the concentration of the final solution presented as follows;

    700 ml contains 1.19 moles of the substance

    Therefore;

    1000 ml will contain 1000/700 * 1.19 = 1.7 moles

    The molarity of the final solution = The number of moles per 1000 ml = 1.7 M.
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