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2 April, 02:54

Write an equation for each acid or base showing its ionization in water, and write the equilibrium constant expression for the weak acid or base. Nitrous Acid, HNO2Ka = 4.0 x 10-4Acetic Acid, HC2H3O2Ka

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  1. 2 April, 05:20
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    HNO₂ (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + NO₂⁻ (aq)

    Ka = [ H₃O⁺]. [NO₂⁻] / [HNO₂]

    CH₃COOH (aq) + H₂O (l) ⇄ CHCOO⁻ (aq) + H₃O⁺ (aq) Ka

    Ka = [CHCOO⁻]. [H₃O⁺] / [CH₃COOH]

    Remember to add the autoinization of water:

    2H₂O (l) ⇄ OH⁻ (aq) + H₃O⁺ (aq) Kw

    Explanation:

    Nitrous acid → HNO₂ (weak acid)

    The ionization in water is:

    HNO₂ (aq) → H⁺ (aq) + NO₂⁻ (aq)

    Let's write the equilibrium:

    HNO₂ (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + NO₂⁻ (aq) Ka

    Ka = [ H₃O⁺]. [NO₂⁻] / [HNO₂]

    Acetic acid → CH₃COOH (weak acid)

    Ionization in water: CH₃COOH (aq) → CHCOO⁻ (aq) + H⁺ (aq)

    Equilibrium: CH₃COOH (aq) + H₂O (l) ⇄ CHCOO⁻ (aq) + H₃O⁺ (aq) Ka

    Ka = [CHCOO⁻]. [H₃O⁺] / [CH₃COOH]
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