What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen?

C3H4N

C2H4N

C4H10N

C2H5N

= C3H4N

Explanation:

We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.

We first calculate the number of moles of each element.

Carbon = 90g/12 g/mol

= 7.5 moles

Hydrogen = 11 g / 1 g/mol

= 11 moles

Nitrogen = 35 g / 14 g/mol

= 2.5 moles

The we get the mole ratio of the elements;

= 7.5/2.5 : 11/2.5 : 2.5 / 2.5

= 3 : 4.4 : 1

= 3 : 4 : 1

Therefore;

The empirical formula will be; C3H4N