Joe tries to neutralize 125mL of 2.0 M HCL with 175mL of 1.0M NaOH. will the neutralization reaction be completed? If not what is the pH of the final solution?

1) The neutralization reaction will mot be completed.

2) pH = 0.6.

Explanation:

1) Will the neutralization reaction be completed?

For the neutralization reaction be completed; The no. of millimoles of the acid must be equal the no. of millimoles of the base.

The no. of millimoles of 125 mL of 2.0 M HCl = MV = (2.0 M) (125.0 mL) = 250.0 mmol.

The no. of millmoles of 175 mL of 1.0 M NaOH = MV = (1.0 M) (175.0 mL) = 175.0 mmol.

∴ HCl will be in excess.

∴ The neutralization reaction will mot be completed.

2) If not what is the pH of the final solution?

[H⁺] = [ (MV) HCl - (MV) NaOH]/V total = (250.0 mmol - 175.0 mmol) / (300.0 mL) = 0.25 M.

∵ pH = - log[H⁺]

∴ pH = - log (0.25) = 0.6.