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20 March, 08:22

A 0.479 g sample of nitrogen, oxygen or neon gas occupies a volume of 265 ml at 157 kpa and 20◦c. what is the molar mass and identity of the gas?

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  1. 20 March, 10:02
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    PV = nRT

    P = 157 kPa = 157 * 10³ Pa

    V = 265 ml = 0.265 l

    T = 20°C = 293 K

    m = 0.479 g

    PV•M = mRT

    M = (mRT) / (PV)

    M = 0.479 g * 8.314 kPa. l / (mol. K) * 293 K / (157 kPa * 0.265 l)

    M ≈ 28.04579 g/mol.

    Hence, the Molar Mass of Dinitrogen or Nitrogen Gas is 28 g.
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