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24 March, 08:24

A student dissolves 10.0 g of sodium sulfate (Na2SO4) in 250.0 mL of water. Calculate the molarity of the solution.

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  1. 24 March, 11:54
    0
    0.281 M

    Explanation:

    M (Na2SO4) = 2*23.0 + 32.1 + 4*16.0 = 142.1 g/mol

    10.0 g * 1 mol / 142.1 g = (10/142.1) mol

    250.0 mL = 0.2500 L

    (10/142.1) mol/0.2500 L = 0.281 mol/L = 0.281 M
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