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6 November, 09:57

How much water must be added to a 25 mL sample of 1.5 M sodium sulfate in order to make it 0.20 M?

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  1. 6 November, 11:26
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    162.5 mL

    Explanation:

    M1*V1 = M2*V2

    M - molarity

    V - volume of solution

    25*1.5 = 0.20 * V2

    V2 = (25*1.5) / 0.20 = 187.5 mL of solution 2.

    We had 25 mL of solution 1, solution 2 should have volume 187.5 mL,

    so we have to add V2 - V1 = 187.5 - 25 = 162.5 mL of water, or ≈ 163 mL
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