Ask Question
9 October, 09:38

Like all equilibrium constants, the value of Kw depends on temperature. At body temperature (37°C), Kw = 2.4 * 10-14. What are the [H3O+] and pH of pure water at body temperature?

+1
Answers (1)
  1. 9 October, 11:48
    0
    pH = 6.8124

    Explanation:

    We know pH decreases with increase in temperature.

    At room temperature i. e. 25⁰c pH of pure water is equal to 7

    We know

    Kw = [H⁺][OH⁻] ... (1)

    where Kw = water dissociation constant

    At equilibrium [H⁺] = [OH⁻]

    So at 37⁰c i. e body temperature Kw = 2.4 * 10⁻¹⁴

    From equation (1)

    [H⁺]² = 2.4 * 10⁻¹⁴

    [H⁺] = √2.4 * 10⁻¹⁴

    [H⁺] = 1.54 * 10⁻⁷

    pH = - log[H⁺]

    = - log{1.54 * 10⁻⁷}

    = 6.812
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Like all equilibrium constants, the value of Kw depends on temperature. At body temperature (37°C), Kw = 2.4 * 10-14. What are the [H3O+] ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers