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7 January, 14:42

A balloon now occupies 9.7L at 25.0°C and 1.00 atm. What temperature was it initially, if it occupied 9.0 L and was in a freezer with a pressure of 0.92 atm?

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  1. 7 January, 16:10
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    -19°C (2 sig. figs.)

    Explanation:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = 1.00atm

    V₁ = 9.7L

    T₁ = 25°C = 298K

    P₂ = 0.92atm

    V₂ = 9L

    T₂ = ?

    T₂ = T₁P₂V₂/P₁V₁

    = 298K (0.92atm/1.00atm) (9.0L/9.7L) = 254K = (254 - 273) °C = - 19°C (2 sig. figs.)
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