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30 August, 14:03

If a container has a volume of 8.00 L of helium at 20.0oC and a pressure at 3.0 atm, what is the new temperature of this gas when the volume is 4.3 L at a pressure of 1.2 atm?

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  1. 30 August, 16:26
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    P1V1/T1 = P2V2/T2

    T2 = P2V2T1/P1V1

    = 1.2*4.3*20/3*8 = 4.3
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