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18 August, 13:55

A bubble of helium gas has a volume of 0.65 L near the bottom of a large

aquarium where the pressure is 3.4 atm and the temperature is 19°C. Determine

the bubble's volume upon rising near the top where the conditions change to 3.2

atm and 36°C.

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Answers (1)
  1. 18 August, 14:10
    0
    0.73L

    Explanation:

    The following data were obtained from the question:

    V1 = 0.65 L

    P1 = 3.4 atm

    T1 = 19°C = 19 + 273 = 292K

    V2 = ?

    P2 = 3.2 atm

    T2 = 36°C = 36 + 273 = 309K

    The bubble's volume near the top can be obtain as follows:

    P1V1 / T1 = P2V2 / T2

    3.4 x 0.65/292 = 3.2 x V2 / 309

    Cross multiply to express in linear form as shown below:

    292 x 3.2 x V2 = 3.4 x 0.65 x 309

    Divide both side by 292 x 3.2

    V2 = (3.4 x 0.65 x 309) / (292 x 3.2)

    V2 = 0.73L

    Therefore, the bubble's volume near the top is 0.73L
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