6K + B2O3 → 3K2O + 2B

How many moles of Boron can be produced if 3650g of B2O3 reacted?

104.84 moles

Explanation:

Given dа ta:

Moles of Boron produced = ?

Mass of B₂O₃ = 3650 g

Solution:

Chemical equation:

6K + B₂O₃ → 3K₂O + 2B

Number of moles of B₂O₃:

Number of moles = mass / molar mass

Number of moles = 3650 g / 69.63 g/mol

Number of moles = 52.42 mol

Now we will compare the moles of B₂O₃ with B from balance chemical equation:

B₂O₃ : B

1 : 2

52.42 : 2*52.42 = 104.84

Thus from 3650 g of B₂O₃ 104.84 moles of boron will produced.