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8 June, 02:50

At a temperature of 273 K, a 400.-milliliter gas sample has a pressure of 760. millimeters of mercury. If the pressure is changed to 380. millimeters of mercury, at which temperature will this gas sample have a volume of 551 milliliters

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  1. 8 June, 04:04
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    188.03K

    Explanation:

    The following data were obtained from the question:

    T1 (initial temperature) = 273K

    V1 (initial volume) = 400mL

    P1 (initial pressure) = 760mmHg

    P2 (final pressure) = 380mmHg

    V2 (final volume) = 551mL

    T2 (final temperature) = ?

    Applying the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas can be obtained as follow:

    P1V1/T1 = P2V2/T2

    760 x 400/273 = 380 x 551/T2

    Cross multiply to express in linear form as shown below:

    760 x 400 x T2 = 273 x 380 x 551

    Divide both side by 760 x 400

    T2 = (273 x 380 x 551) / (760 x 400)

    T2 = 188.03K.

    Therefore, at a temperature of 188.03K, the gas sample will have a volume of 551mL
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