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Today, 14:08

How much heat (energy) would need to be absorbed by 1.5 g of liquid

water to cause a temperature change of 30.45 °C? The specific heat of

water is 4.18 J/gºC.

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Answers (1)
  1. Today, 14:50
    0
    190.92 J

    Explanation:

    By using the formula Q = mcΔT

    Q = 1.5g * 4.18 J/g°C * 30.45°C

    = 190.92 J
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