Consider the reaction between barium chloride and sodium sulphate. If 25.0 mL of 0.75 M barium chloride react, how many grams of solid are produced?

C=n/v = > n=CxV (convert V=25ml=0.025L)

n=0.75x0.025 = 0.01875

m=n/M

m = 0.01875 / (108+35.5x2) = 3.35625g

I'm pretty sure that's the way to solve it but the answer is pretty small that kinda make me uncomfortable