Ask Question
17 May, 08:43

A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 30.0 atm, what was the volume of the sample

+4
Answers (1)
  1. 17 May, 09:45
    0
    0.0613 L

    Explanation:

    Given data

    Initial pressure (P₁) : 1.00 atm Initial volume (V₁) : 1.84 L Final pressure (P₂) : 30.0 atm Final volume (V₂) : ?

    Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

    P₁ * V₁ = P₂ * V₂

    V₂ = P₁ * V₁ / P₂

    V₂ = 1.00 atm * 1.84 L / 30.0 atm

    V₂ = 0.0613 L
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the sample ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers