Ask Question
4 January, 02:19

What mass of H₂O is formed when excess H₂ reacts with 64 g of O₂? *

2H2+O2 - ->2H2O

Answer: 72g

+4
Answers (1)
  1. 4 January, 05:19
    0
    72g of H2O.

    Explanation:

    We'll begin by writing the balanced equation for the reaction. This is given below:

    2H2 + O2 - >2H2O

    Next, we'll determine the mass of O2 that reacted and the mass of H2O produced from the balanced equation.

    This is illustrated below:

    Molar Mass of O2 = 16x2 = 32g/mol

    Molar Mass of H2O = (2x1) + 16 = 18g/mol

    Mass of H2O from the balanced equation = 2 x 18 = 36g

    Summary:

    From the balanced equation above,

    32g of O2 reacted to produce 36g of H2O.

    Now, we can obtain the mass of H2O produced when 64g of O2 react as follow:

    From the balanced equation above,

    32g of O2 reacted to produce 36g of H2O.

    Therefore, 64g of O2 will react to produce = (64 x 36) / 32 = 72g of H2O.

    From the calculations made above, 72g of H2O is produced from the reaction.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What mass of H₂O is formed when excess H₂ reacts with 64 g of O₂? * 2H2+O2 - ->2H2O Answer: 72g ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers