What is the specific heat of a substance if 1560 cal are required to raise temperature of a 312 g substance by 15 degrees celsius?

The Specific Heat formula is:

c = ΔQ / (m * ΔT)

Where:

c: Specific Heat, in J / (kg. K)

ΔQ: Heat required for the temperature change, in J

ΔT: Temperature change, in K

m : Mass of the object, in kg

So substitute the numbers in; Calories should be converted into joules

c = 1560 (4.184) / (312*15)

c = 1394.666