How much Sr (OH) 2 • 8 H2O (M = 265.76) is needed to prepare 250.0 mL of solution in which [OH-] = 0.100 M?

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Chemistry

Bentley

31 January, 14:38

How much Sr (OH) 2 • 8 H2O (M = 265.76) is needed to prepare 250.0 mL of solution in which [OH-] = 0.100 M?

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Keira Stevenson · Answer 1

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We do as follows:

Molarity = mol / L = 0.100 mol OH / L

0.100 mol OH / L (.250 L) (1 mol Sr (OH) 2 • 8 H2O / 2 mol OH) (265.76 g / 1 mol) = 3.322 g Sr (OH) 2 • 8 H2O needed