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27 February, 20:30

In a calorimeter, 6.68 kJ of heat was absorbed by 20 g of ice. What is the enthalpy of fusion of the ice? q=m∆ahf

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  1. 27 February, 21:14
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    Using the enthalpy of fusion formula we have:

    q=mlHf

    q=6.68 or 6680 J, m = 20 we need to find lHf

    6680 = (20) (lHf)

    lHf=6680/20

    lHf = 334J/g
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