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29 October, 18:38

If 5.100 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temperature of the water?

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  1. 29 October, 21:32
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    C6H12 = 6x12 + 6x1 = 78.

    The equation indicates that 2x78 = 156g benzene will produce 6542kJ.

    Using proportions you can then calculate that

    x/6542kJ = 7.9g / 156g

    x = 331.3kJ = 331300J.

    heat = mass x ΔT x 4.18J/g°

    ΔT = 331300J / (5691g x 4.18J/g°) = 13.9°

    final temp = 21 + 14° = 35°C
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