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8 April, 05:53

Consider the reaction.

N2 (g) + 3H2 (g) 2NH3 (g)

At equilibrium, the concentrations of the different species are as follows.

[NH3] = 0.105 M

[N2] = 1.1 M

[H2] = 1.50 M

What is the equilibrium constant for the reaction at this temperature?

a. 0.0030

b. 0.030

c. 34

d. 340

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Answers (1)
  1. 8 April, 08:31
    0
    N2 (g) + 3H2 (g) 2NH3 (g)

    Constant equilibrium, Ke = [NH3]eq^2 / { [N2]eq * [H2]eq^3 }

    [NH3]eq = 0.105 M

    [N2]eq = 1.1 M

    [H2]eq = 1.50 M

    Ke = 0.105^2 / [ 1.1 * (1.50) ^3 } = 0.00297 = 0.0030

    Answer: option a. 0.0030
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