Click the DeltaH is an Extensive Property button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, ΔH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2.

Reaction 1: C3H8 (g) + 5O2 (g) →3CO2 (g) + 4H2O (g), ΔH1=-2043 kJ

Reaction 2: 4C3H8 (g) + 20O2 (g) →12CO2 (g) + 16H2O (g), ΔH2=?

Question

Chemistry

Mcgrath

25 July, 10:27

Click the DeltaH is an Extensive Property button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, ΔH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2.

Reaction 1: C3H8 (g) + 5O2 (g) →3CO2 (g) + 4H2O (g), ΔH1=-2043 kJ

Reaction 2: 4C3H8 (g) + 20O2 (g) →12CO2 (g) + 16H2O (g), ΔH2=?

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Answers (1)

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Cassie Solis · Answer 1

Calculate the change in enthalpy for Reaction 2.

Reaction 1: C3H8 (g) + 5O2 (g) →3CO2 (g) + 4H2O (g), ΔH1=-2043 kJ

Reaction 2: 4C3H8 (g) + 20O2 (g) →12CO2 (g) + 16H2O (g), ΔH2=?

An extensive property is one whose value depends on the amount of material.

The change of enthalpy is proportional to the quantity, then given that the equation 2 is the equation 1 times 4, the change of enthalpy of equation 2 is 4 times the change of enthalpy of equation 1.

ΔH2 = 4*ΔH1 = 4 * (-2043 kJ) = - 8172 kJ

Answer: - 8172 kJ