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Write complete ionic equation to show the reaction of aqueous lead (II) nitrate with aqueous potassium sulfate to form solid lead (II) sulfate and aqueous potassium nitrate.

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  1. Yesterday, 20:40
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    The correct answer to this question is this one:

    Pb (N O3) 2 (aq) + K2 S O4 (aq) →PbS O4 (s) + 2KN O3 (aq)

    Everything except the lead sulfate is soluble, so they all dissociate.

    P b 2 + + 2N O-3 + 2 K + + S O 2 - 4 →PbS O4 (s) + 2 K + + 2N O-3

    Cancel out stuff that appears on both sides, and your net ionic equation is

    P b 2 + (aq) + S O 2 - 4 (aq) →PbS O4 (s)
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