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20 August, 05:21

When 10 grams of copper and 10 grams of iodine are mixed, what is the theoretical yield of copper I iodide? 2Cu + I2 → 2CuI

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  1. 20 August, 08:02
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    Moles of Cu: 10 / 63.5 = 0.157 mol

    Moles of I2: 10 / 254 = 0.039 mol

    I2 is the limiting reactant, therefore theoretical yield of CuI (I) is 0.039 mol, equating to 0.039 * 190.5 = around
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