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6 October, 11:36

Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 10.0 atm.?

Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 10.0 atm.

Calculate the work, w, if the gas expands against a constant external pressure of 1.00 atm exerted by the surroundings to a final volume of 15.0 L.

Now calculate the work done if this process is carried out in two steps: Step 1: First let the gas expand against a constant external pressure of 5.00 atm to a volume of 3.00 L. Step 2: Now let the gas expand to 15.0 L against a constant external pressure of 1.00

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  1. 6 October, 11:58
    0
    Work = - Pressure external*Volume change

    -1 atm * (20 - 1) = - 19 atm-L.

    1 atm-L = 101.324999971 J

    So - 19 * 101.32 = - 1925 J

    B.

    Calculate each step individually then sum the answers.

    For step 1)

    -5 * (4-1) = - 15 atm-L

    step 2)

    -1 * (20-4) = - 16 atm-L

    Thus total work = - 31 atm-L

    convert to joules,

    -3141 J
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