SO2Cl2 decomposes in a first-order process with a half-life of 4.88 * 103 s. If the original concentration of SO2Cl2 is 0.011 M, how many seconds will it take for the SO2Cl2 to reach 0.0032 M?

Question

Chemistry

Mcgee

25 June, 11:08

SO2Cl2 decomposes in a first-order process with a half-life of 4.88 * 103 s. If the original concentration of SO2Cl2 is 0.011 M, how many seconds will it take for the SO2Cl2 to reach 0.0032 M?

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Hailie Sharp · Answer 1

The amount of substance after n half-lives is calculated through the equation,

A (n) = A (0) x (0.5) ^t/h

where A (n) is the amount of n half-lives, A (0) is the original amount, t is the total time and h is the half-life.

Substituting the known values,

Basis is 1L,

0.0032 = (0.011) x (0.5) ^ (t/4.88x10^3s)

The value of t from the generated equation is equal to 8693.0 s or also equal to 8.693 x 10^3 s.