When heated, KClO3 decomposes into KCl and O2. If this reaction produced 88.4 g of KCl, how much O2 was produced (in grams) ? 2KClO_3--->2KCl+3O_2. A) 2 (KClO_3) = 245.096 B) 2KCl=149.102g C) 3O_2=95.995

Mass of KCl = 88.4g

Molar mass of KCl=39+35.5

=74.5

The Moles of KCl = 88.4/74.5

=1.186

If for the 2 moles of KCl there are 3 moles of oxygen

so

1 mole of KCl will give=3/2=1.5 moles of oxygen

1.186 moles of KCl will give = 1.5*1.186=1.779 oxygen

32 the molar mass of oxygen

so its mass will be

1.779 * 32=56.928

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