If Plank's constant is 6.6 x 10 (-34) J/Hz, then what is the approximate frequency of a photon having an energy of 3 x 10 (-19) Joules?

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  1. Anezka
    Energy of photon = hc/λ. frequency = c/λ. so energy = h x frequency. frequency = energy/h = 3x10^-19 / 6.6 x 10^-34 = 4.54 x 10^14 Hz
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