When a solution of barium nitrate and a solution of copper (II) sulfate are mixed, a chemical reaction produces solid barium sulfate, which sinks to the bottom, and a solution of copper (II) nitrate. Suppose some barium nitrate is dissolved in 120.00 g of water and 8.15 g of copper (II) sulfate is dissolved in 75.00 g of water. The solutions are poured together, and a white solid forms. After the solid is filtered off, it is found to have a mass of 10.76 g. The mass of the solution that passed through the filter is 204.44 g. What mass of barium nitrate was used in the reaction?

Question

Chemistry

Natalya

7 April, 08:37

When a solution of barium nitrate and a solution of copper (II) sulfate are mixed, a chemical reaction produces solid barium sulfate, which sinks to the bottom, and a solution of copper (II) nitrate. Suppose some barium nitrate is dissolved in 120.00 g of water and 8.15 g of copper (II) sulfate is dissolved in 75.00 g of water. The solutions are poured together, and a white solid forms. After the solid is filtered off, it is found to have a mass of 10.76 g. The mass of the solution that passed through the filter is 204.44 g. What mass of barium nitrate was used in the reaction?

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Answers (1)

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Gianna Little · Answer 1

The total mass of the products is 10.76 g + 204.44 g = 215.20 g.

The masses of all the reactants but one are known so,

215.20 g - 120.00 g - 8.15 g - 75.00 g = 12.05 g

12.05 g is the mass of the unweighed barium nitrate.