Answer the following questions:

If a sample emits 1000 counts per second when the detector is 1 meter from the sample, how many counts per second would be observed when the detector is 2 meters from the sample?

1. Using the sample, how many counts per second would be observed when the detector is 10 meters away from the sample?

2. If Nitrogen-14 absorbs an alpha particle and then emits a Hydrogen-1, what is the resulting nucleus?

3. If Au-185 emits an alpha particle, what is the nucleus formed?

4. What nucleus emits an alpha particle and forms Th-234?

5. If Th-234 emits a beta particle, what nucleus

The relationship of radiation with distance obeys the inverse square law. Therefore, doubling the distance decrease the radiation by a factor of 4. The new count is 250.

1) Applying the same principle, the count decreases by a factor of 100. The new count is 10

2) An alpha particle is 4He2 and the Hydrogen can be represented as 1H1

14N7 + 4He2 - 1H1

= 17X8

Proton number 8 belongs to Oxygen. Therefore, the resultant nucleus is:

17O8

3) 185Au79 - 4He2

= 181Ir77

4) X - 4He2 = 234Th90

X = 238U92

5) Beta emission results in the same nucleon number but an increase in the proton number; therefore, the result is:

234Pa91