A gas occupies a 1.5 L container at 25 degrees Celsius and 2.0 atm. If the gas is transferred to a 3.0 L container at the same temperature, what will be its new pressure?

a) 3.0 atm

b) 2.0 atm

c) 1.0 atm

d) 4.0 atm

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 = P2V2

P2 = P1 x V1 / V2

P2 = 2.0 x 1.5 / 3

P2 = 1 atm