Which set of numbers gives the correct possible values of l for n = 2?

0

0, 1

0, 1, 2

0, 1, 2, 3

For a given principal quantum number or n, the corresponding angular quantum number or l is equivalent to a range between 0 and (n-1). This means that the angular quantum number for a principal quantum number of 2 is equivalent to:

l = 0 - > (n-1) = 0 - > (2-1) = 0 - > 1

So the answer is 0, 1