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13 October, 17:24

A container of gas is at a pressure of 1.3 x 10^5 pa and a volume of 6.0 m^3. how much work is done by the gas if it expands at a constant pressure to twice its initial volume

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  1. 13 October, 21:01
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    For the answer to the question above, since the process is carried out at constant pressure,

    work = P (V1-V2)

    = 1.3 E5 (6-12) = - 7.8 E5 N. m (in this case the work is made by the system, so it is negative if work made on the system then it should be positive)
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