To make 2.00 L of 0.300 M sulfuric acid, how many mL of a 1.00 M stock solution should be used?

We are given with

M1 = 1.00 M

M2 = 0.300 M

V2 = 2.00 L

We are asked to get V1

Using material balance

M1 V1 = M2 V2

Substituting the given values

1.00 V1 = 0.300 M (2.00 L)

V1 = 0.600 L or 600 mL

THe volume needed is 600 mL