A solution contains 180 g of glucose (C6H12O6) and 162 g of water. What is the mole fraction of glucose?

The choices are:

a. 1.0

b. 10.0

c. 0.0010

d. 0.10

e. 0.010

Molar mass glucose = 180.1559 g/mol

number of moles solute:

n = m / mm

n = 180 / 180.1559

n = 0.999 moles

number of moles solvent:

molar mass water = 18.01528 g/mol

n = m / mm

n = 162 / 18.01528

n = 8.992 moles

Mole fraction total:

moles solut + moles solvent : 0.999 + 8.992 = > 9.991 moles

Therefore mole fraction of glucose is:

fraction molar = moles of solute / moles total

= 0.999 / 9.991

=> 0.010

Answer E