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12 August, 04:36

What is the maximum volume of 0.788M CaCl2 solution that can be prepared using 85.3g CaCl2

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  1. 12 August, 06:01
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    Concentration=moles/volume

    Volume=moles/concentration

    To find the number of moles, you divide the mass of CaCl2 by its molar mass. The molar mass of CaCl2 is: 2x35.45 (molar mass Cl) + 40.08 (molar mass Ca)

    Molar mass = 110.98g/mol

    Moles=m/molar mass

    Moles=85.3/110.98

    Moles=0.7686069562

    Then you calculate the volume:

    Volume = 0.7686069562/0.778

    Volume = 0.9879266789L

    =0.988L

    Therefor the max volume that can be prepared is 0.998L
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