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16 September, 00:32

Given that the k sp for caf2 at 25°c is 3.9 * 10-11, will a precipitate form when 0.10 l of 2.3 * 10-4 m cacl2 is added to 0.50 l of 5.0 * 10-3 m naf? assume volumes are additive.

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  1. 16 September, 01:14
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    Given:

    Ksp (CaF2) at 25 degrees Celsius = 3.9 x10^-11

    volume of CaCl2 = 100 ml

    concentration of CaCl2 = 2.3 x 10^-4 m

    Volume of NaF = 500 ml

    concentration of NaF = 5.0x10^-3 m

    Total volume = 100 + 500 = 600 ml

    balanced chemical equation:

    2NaF + CaCl2 = = = > CaF2 + 2NaCl

    calculate the number of moles NaF and CaCl2. Then determine the resulting moles of CaF2 (based on the limiting reactant) and find the concentration of CaF2. If it is more than the Ksp, meaning there will be a precipitate.
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