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8 April, 13:41

How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?

A. 4.1498 * 1024

B. 4.1498 * 1023

C. 8.299 * 1024

D. 8.299 * 1023

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Answers (2)
  1. 8 April, 16:13
    0
    Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of formula units or atoms or molecules into number of moles.

    6.89 mol KOH (6.022 x 10^23 formula units / mole) = 4.1498 x 10^24 formula units

    Therefore, the correct answer is option A.
  2. 8 April, 16:48
    0
    I believe there would be A. 4.1498x10^24 formula units in 6.89 moles of KOH.
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