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How many joules are needed to warm 675 grams of water (specific heat = 4.186 J/g degrees Celsius) from 12 degrees Celsius to 85 degrees Celsius?

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  1. Today, 01:40
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    85-12 = 73 degrees needed

    4.186 J/degree Celsius, so

    73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees

    there are 675 grams, so 305.578 * 675 = 206265.15 J

    2.06 x 10^5 J are needed
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