Ask Question
18 July, 19:52

Calculate the heat change in calories for condensation of 20.0 g of steam at 100∘C.

+4
Answers (1)
  1. 18 July, 20:43
    0
    The latent heat of vaporization of steam is equal to its latent heat of condensation. The heat released is given by:

    Q = ml

    Q = 20 x 2257 joules/gram

    Q = 45.14 kJ of heat is removed from the steam

    1 calorie = 4.184 kJ

    45.14 kJ = 10.8 cal of energy

    The energy removed is 10.8 calories
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calculate the heat change in calories for condensation of 20.0 g of steam at 100∘C. ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers