I WIll upvote for answer

Balance the following reaction Fe^2 O ^3 + HCI+FeCI^3+H^2O

Let's balance step by step. We'll start with Iron (Fe)

Fe2O3 + HCl - - > FeCl3 + H2O

We have 2 Fe on the left, and only one on the right, so we'll double the Fe on the right

Fe2O3 + HCl - - > 2FeCl3 + H2O

Now we have six Cl on the right, and only one on the left, so we'll multiply the Cl by six on the left

Fe2O3 + 6HCl - - > 2FeCl3 + H2O

Finally, we can balance the water, as we have 6 H and 3 O on the left, and 2 H and one O on the right, so we can triple the H2O on the right

Fe2O3 + 6HCl - - > 2FeCl3 + 3H2O

The equation has been balanced.